-15-4x^2=-60

Solution for -15-4x^2=-60 equation:

-15-4x^2=-60

We move all terms to the left:

-15-4x^2-(-60)=0

We add all the numbers together, and all the variables

-4x^2+45=0

a = -4; b = 0; c = +45;
Δ = b2-4ac
Δ = 02-4·(-4)·45
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*-4}=\frac{0-12\sqrt{5}}{-8}
=-\frac{12\sqrt{5}}{-8}
=-\frac{3\sqrt{5}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*-4}=\frac{0+12\sqrt{5}}{-8}
=\frac{12\sqrt{5}}{-8}
=\frac{3\sqrt{5}}{-2}
$